Question

What are the ratios of the six trigonometric functions?

Accepted Answer

$$\sin{	heta} = \frac{	ext{opposite}}{	ext{hypotenuse}} $$

$$\cos{	heta} = \frac{	ext{adjacent}}{	ext{hypotenuse}} $$

$$	an{	heta} = \frac{	ext{opposite}}{	ext{adjacent}} $$

$$\csc{	heta} = \frac{	ext{hypotenuse}}{	ext{opposite}} $$

$$\sec{	heta} = \frac{	ext{hypotenuse}}{	ext{adjacent}} $$

$$\cot{	heta} = \frac{	ext{adjacent}}{	ext{opposite}} $$

Flashcard 19 - Math Flashcard Set for the SAT Exam

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