If there are 3 given pieces of information and a fourth one is missing.
Here’s one that should be solved using proportions: If John can build 8 tables in 3 days, how long will it take him to build 20 tables? One possible proportion could be:
\[\dfrac{8 \text{ tables}}{3 \text{ days}} = \dfrac{20 \text{ tables}}{x \text{ days}}\]