Flashcard 9 - Math Flashcard Set for the ACT

distance = \(\sqrt{(x_2-x_1 )^2 + (y_2-y_1 )^2}\), where \((x_1,y_1 ),(x_2,y_2)\) are 2 points

Notice the similarity between this and the Pythagorean theorem: \(c^2 = a^2 + b^2\)

midpoint = \(\left(\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}\right)\)

Notice that this is the average of the 2 x values and the average of the 2 y values