Flashcard 8 - Mathematics: Algebraic Reasoning Flashcard Set for the TSIA2

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The correct answer is:

substitute \(-2\) into all \(x\) of the function \(f(x)\) and simplify to get the answer


Explanation:

When we want to evaluate a function \(f(x)\) at a value \(x=a\), we simply plug in \(a\) into the function. This means substituting \(a\) into all \(x\) of the function given and arriving at an answer. The evaluation of the function \(f(x)\) at \(x=-2\) is shown below.

\[f(x) = x^2 - 2x + 5\] \[f(-2) = (-2)^2 -2(-2) + 5\] \[f(-2) = 4 + 4 + 5\] \[f(-2) = 13\]

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