Flashcard 13 - Mathematics: Algebraic Reasoning Flashcard Set for the TSIA2

\[8x^{9}y^{3}\]

Let’s simplify the expression inside the parentheses:

\[\left(\frac{2xy}{x^{-2}}\right)^{3}\] \[= (2xyx^{2})^{3}\] \[= (2x^{3}y)^{3}\]

Now, we can raise the expression inside the parentheses to the third power.

\[(2x^{3}y)^{3}\] \[= 2^{3}(x^{3})^{3} y^{3}\] \[= 8x^{9}y^{3}\]