Flashcard 9 - 11th Grade Mathematics: Number and Operations Flashcard Set for the SBAC

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After isolating the radical expression, squaring both sides, and doing the appropriate algebra, you do get a solution of:

\[\frac{62}{3}\]

However, after substitution in the original equation, you get:

\[\sqrt{64} +8 = 0\]

You only consider positive values for the square root unless there is specifically a negative sign in front of it. So \(8 + 8 \ne 0\) and the solution does not work. There is no real solution.