If $$\sin(\theta) = \frac{1}{2}$$, where $$\theta$$ is in the 1st quadrant, then $$\cos(180 - \theta) =$$ `____`

Flashcard 13 - 11th Grade Mathematics: Geometry Flashcard Set for the SBAC

\[-\dfrac{\sqrt{3}}{2}\]

\[\sin(30^o) = \frac{1}{2}\]

So, $\theta = 30^o$ (since it’s in the first quadrant).

Now, $\cos(180-\theta) = \cos(180-30) = \cos(150^o) = -\dfrac{\sqrt{3}}{2}$.

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