Flashcard 14 - 11th Grade Mathematics: Functions Flashcard Set for the SBAC

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\[cos\theta\]

Explanation:

\(\tan\theta \sin\theta +\) ____\(= \sec\theta\)

Put x in for the blank.

\[\frac{\sin\theta}{\cos\theta} \sin\theta + x = \frac{1}{\cos\theta}\] \[\frac{\sin^{2}\theta}{\cos\theta} + x = \frac{1}{\cos\theta}\] \[x = \frac{1}{\cos\theta}-\frac{\sin^{2}\theta}{\cos\theta}\] \[x=\frac{1-\sin^{2}\theta}{\cos\theta}\] \[x=\frac{\cos^{2}\theta}{\cos\theta}\] \[x=\cos\theta\]

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