Flashcard 11 - 11th Grade Mathematics: Algebra Flashcard Set for the SBAC

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The correct answer is:

\[(x-3)(x^2+3x+9)\]

Explanation:

To factor a difference of 2 perfect cubes use this formula:

\(a^3-b^3 = (a-b)(a^2+ab+b^2)\) where a = x and b = 3

Now:

\[x^3-3^3 = (x-3)(x^2+x \cdot 3 + 3^2)\]

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