Flashcard 1 Math Flashcard Set for the PERT



The correct answer is:

\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \ \end{array} It is used to find the zeroes of a function, or where the function crosses the x-axis.


The quadratic formula is used to solve for the roots of a quadratic equation (aka “equation of degree 2”) in the form where is the variable and , and are constants. “Solving for the root” is another phrase for “solving for the zeroes of the function” or “solving for the value of the variable as the graph of the quadratic formula crosses the x-axis”. A quadratic equation has two roots or two values for .