Question

What is the proper order of operations for this equation? 

$$7(6-5)\;+\;\frac{8}{2}$$

Accepted Answer

$$7(6-5) + \frac{8}{2} = 7(1) + \frac{8}{2} = 7 + \frac{8}{2} = 7 + 4 = 11$$

Answer

$$7(6-5)+ \frac{8}{2} = 42-35+ \frac{8}{2} = 7+ \frac{8}{2} = \frac{15}{2} = 7.5$$

Answer

$$7(6-5)+ \frac{8}{2} = 7(6-5)+ \frac{8}{2} = 7(6-5)+4 = 7(6)-5+4 = 42-5+4 = 41$$

Answer

$$7(6-5)+ \frac{8}{2} = 7(1)+ \frac{8}{2} = \frac{7(9)}{2} = \frac{63}{2} = 31.5$$

Question 7 - Mathematics Practice Test for the ACT