Find the missing term: $$\frac{7x}{16y}=\frac{?}{64x^{2}y}$$

Flashcard 9 - Subtest II: Mathematics Flashcard Set for the CSET Multiple Subjects Test

\[28x^{3}\]

We need to change the denominator $16y$ to $64x^{2}y$

Multiplying by $\frac{4x^{2}}{4x^{2}}$ will do that.

\[\frac {4x^{2}}{4x^{2} }\cdot \frac{7x}{16y}= \frac{28x^{3}}{64x^{2}y}\]

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