Flashcard 8 - Subtest II: Mathematics Flashcard Set for the CSET Multiple Subjects Test

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The correct answer is:

\[\frac{24a+11}{20a{2}}\]

Explanation:

\[\frac{6}{5a}+\frac{11}{20a^{2}}\] \[\frac{4a}{4a} \cdot \frac{6}{5a}+\frac{11}{20a^{2}}\] \[\frac{24a}{20a^{2}}+\frac{11}{20a^{2}}\] \[\frac{24a+11}{20a^{2}}\]

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