Flashcard 20 - Math Flashcard Set for the CBEST

360°

The sum of the interior angles in degrees of any quadrilateral is 360.
This is solved using the formula, \(Sum\,of\,Interior\,Angles = (n - 2) \cdot 180\) where \(n\) is the number of sides in any polygon.
For a quadrilateral, the \(Sum\,of\,Interior\,Angles = (4-2) \cdot 180 = 360\).
The same is true of the angle formed by rotating the radius of a circle one complete turn.