Question 40 - Math Practice Test for the PSAT/NMSQT Exam

Determine which line is perpendicular to

\[\frac{y}{2} - 1 = 3(x + 1)\]

\[x = -3 (-5 + 2y)\]
\[y = 6x - 4\]
\[6x = -y + 15\]
\[\frac{1}{2}(y - 3) = 3(x - 5)\]

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