Question

Solve for the roots of this equation:   

$$y = 2x^2 + 3x -9$$

Accepted Answer

$$x = \frac{3}{2} \; 	ext{and} \; x = -3$$

Answer

$$x = -\frac{3}{2} \; 	ext{and} \; x = 3$$

Answer

$$x = 0 \; 	ext{and} \; x = -\frac{3}{2}$$

Answer

$$x = 0 \; 	ext{and} \; x = \frac{3}{2}$$

Question 37 - Math Practice Test for the PSAT/NMSQT Exam