Flashcard 1 - Math Flashcard Set for the PSAT/NMSQT Exam
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\[x = \frac{4 \pm \sqrt{(-4)^2 - 4(3)(5)}}{2(3)}\]
Explanation:
The quadratic formula is:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]From the given equation, the coefficients have the following values: a = 3, b = -4, and c = 5
Plugging them into the quadratic formula, we have:
\[x = \frac{4 \pm \sqrt{(-4)^2 - 4(3)(5)}}{2(3)}\]All Flashcard Sets for the PSAT/NMSQT Exam are now available as downloadable PDFs