Flashcard 1 - Math Flashcard Set for the PSAT/NMSQT Exam

\[x = \frac{4 \pm \sqrt{(-4)^2 - 4(3)(5)}}{2(3)}\]

The quadratic formula is:

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

From the given equation, the coefficients have the following values: a = 3, b = -4, and c = 5

Plugging them into the quadratic formula, we have:

\[x = \frac{4 \pm \sqrt{(-4)^2 - 4(3)(5)}}{2(3)}\]