Question

Divide [$$6{x^5}{y^3} + 18{x^4}y - 9xy + 36$$]  by [$$9xy$$].

Accepted Answer

$$\frac{{2{x^4}{y^2}}}{3} + 2{x^3} - 1 + \frac{4}{{xy}}$$

Answer

$$\frac{{6{x^4}{y^2}}}{9} + \frac{{18{x^3}}}{9} - \frac{9}{9} + \frac{{36}}{{9xy}}$$

Answer

$$\frac{{2{x^5}{y^3}}}{{3xy}} + \frac{{2{x^4}y}}{{xy}} - \frac{{xy}}{{xy}} + \frac{4}{{xy}}$$

Answer

$$\frac{{2{x^5}{y^3}}}{3} + 2{x^4}y - 1 + \frac{4}{{xy}}$$

Question 13 - Mathematics Practice Test for the HiSET Test